If the given vectors \[(-bc,\,{{b}^{2}}+bc,\,{{c}^{2}}+bc),\] \[({{a}^{2}}+ac,\,-ac,\,{{c}^{2}}+ac)\] and \[({{a}^{2}}+ab,\,{{b}^{2}}+ab,\,-ab)\] are coplanar, where none of a, b and c is zero, then

\[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}=1\]

\[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}=bc+ca+ab\]

If the given vectors \[(-bc,\,{{b}^{2}}+bc,\,{{c}^{2}}+bc),\] \[({{a}^

1.	If the given vectors \[(-bc,\,{{b}^{2}}+bc,\,{{c}^{2}}+bc),\] \[({{a}^{2}}+ac,\,-ac,\,{{c}^{2}}+ac)\] and \[({{a}^{2}}+ab,\,{{b}^{2}}+ab,\,-ab)\] are coplanar, where none of a, b and c is zero, then
A.	\[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}=1\]
B.	\[bc+ca+ab=0\]
C.	\[a+b+c=0\]
D.	\[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}=bc+ca+ab\]
Answer» C. \[a+b+c=0\]

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If the given vectors \[(-bc,\,{{b}^{2}}+bc,\,{{c}^{2}}+bc),\] \[({{a}^{2}}+ac,\,-ac,\,{{c}^{2}}+ac)\] and \[({{a}^{2}}+ab,\,{{b}^{2}}+ab,\,-ab)\] are coplanar, where none of a, b and c is zero, then

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