If the function \[y=\frac{ax+b}{(x-1)(x-4)}\] has turning point at \[P(2,-1)\], then

If the function \[y=\frac{ax+b}{(x-1)(x-4)}\] has turning point at \[P

1.	If the function \[y=\frac{ax+b}{(x-1)(x-4)}\] has turning point at \[P(2,-1)\], then
A.	\[a=b=1\]
B.	\[a=b=0\]
C.	\[a=1,b=0\]
D.	\[a=b=2\]
Answer» D. \[a=b=2\]

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If the function \[y=\frac{ax+b}{(x-1)(x-4)}\] has turning point at \[P(2,-1)\], then

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