If the function \[f(x)=\left\{ \begin{align} & \frac{k\cos x}{\pi -2x},\text{when }x\ne \frac{\pi }{2} \\ & 3,\ \ \ \ \ \ \ \ \ \text{when }x=\frac{\pi }{2} \\ \end{align} \right.\] be continuous at \[x=\frac{\pi }{2}\], then k =

If the function \[f(x)=\left\{ \begin{align} & \frac{k\cos x}{\pi -

1.	If the function \[f(x)=\left\{ \begin{align} & \frac{k\cos x}{\pi -2x},\text{when }x\ne \frac{\pi }{2} \\ & 3,\ \ \ \ \ \ \ \ \ \text{when }x=\frac{\pi }{2} \\ \end{align} \right.\] be continuous at \[x=\frac{\pi }{2}\], then k =
A.	3
B.	6
C.	12
D.	None of these
Answer» C. 12

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If the function \[f(x)=\left\{ \begin{align} & \frac{k\cos x}{\pi -2x},\text{when }x\ne \frac{\pi }{2} \\ & 3,\ \ \ \ \ \ \ \ \ \text{when }x=\frac{\pi }{2} \\ \end{align} \right.\] be continuous at \[x=\frac{\pi }{2}\], then k =

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