If the function\[f(x)=\frac{x(x-2)}{{{x}^{2}}-4},x\ne \pm 2\]is continuous at\[x=2\], then what is \[f(2)\] equal to?

If the function\[f(x)=\frac{x(x-2)}{{{x}^{2}}-4},x\ne \pm 2\]is contin

1.	If the function\[f(x)=\frac{x(x-2)}{{{x}^{2}}-4},x\ne \pm 2\]is continuous at\[x=2\], then what is \[f(2)\] equal to?
A.	0
B.	\[\frac{1}{2}\]
C.	1
D.	2
Answer» C. 1

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If the function\[f(x)=\frac{x(x-2)}{{{x}^{2}}-4},x\ne \pm 2\]is continuous at\[x=2\], then what is \[f(2)\] equal to?

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