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1. |
if the fourth proportional of \({7}{{}}\frac{1}{5}\), \({4}{{}}\frac{1}{5}\), \({3}{{}}\frac{6}{7}\) is k, then \(\frac{4k+1}{4k-1}\) = |
A. | \(\frac{4}{5}\) |
B. | \(\frac{6}{5}\) |
C. | \(\frac{7}{5}\) |
D. | \(\frac{5}{4}\) |
Answer» E. | |