1.

if the fourth proportional of \({7}{{}}\frac{1}{5}\), \({4}{{}}\frac{1}{5}\), \({3}{{}}\frac{6}{7}\) is k, then \(\frac{4k+1}{4k-1}\) =

A. \(\frac{4}{5}\)
B. \(\frac{6}{5}\)
C. \(\frac{7}{5}\)
D. \(\frac{5}{4}\)
Answer» E.


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