If the extremities of the base of an isosceles triangle are the points \[(2a,0)\] and \[(0,a)\] and the equation of one of the sides is \[x=2a\], then the area of the triangle is

\[\frac{25{{a}^{2}}}{2}sq.\]units

\[\frac{5}{2}{{a}^{2}}sq.\]units

If the extremities of the base of an isosceles triangle are the points

1.	If the extremities of the base of an isosceles triangle are the points \[(2a,0)\] and \[(0,a)\] and the equation of one of the sides is \[x=2a\], then the area of the triangle is
A.	\[5{{a}^{2}}sq\]. units
B.	\[\frac{5}{2}{{a}^{2}}sq.\]units
C.	\[\frac{25{{a}^{2}}}{2}sq.\]units
D.	None of these
Answer» C. \[\frac{25{{a}^{2}}}{2}sq.\]units

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If the extremities of the base of an isosceles triangle are the points \[(2a,0)\] and \[(0,a)\] and the equation of one of the sides is \[x=2a\], then the area of the triangle is

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