If the equation of the locus of a point equidistant from the points (\[{{a}_{1,}}{{b}_{1}}\]) and (\[{{a}_{2,}}{{b}_{2}}\]) is (\[{{a}_{1,-}}{{a}_{2}}\])x+(\[{{b}_{1,-}}{{b}_{2}}\])\[y+c=0\] then the value of c is

\[{{a}_{1}}^{2}+{{a}_{2}}^{2}+{{b}_{1}}^{2}-{{b}_{2}}^{2}\]

\[\frac{1}{2}({{a}_{2}}^{2}+{{b}_{2}}^{2}-{{a}_{1}}^{2}-{{b}_{1}}^{2})\]

\[\frac{1}{2}({{a}_{1}}^{2}+{{a}_{2}}^{2}-{{b}_{1}}^{2}-{{b}_{2}}^{2})\]

\[\sqrt{{{a}_{1}}^{2}+{{b}_{2}}^{2}-{{a}_{2}}^{2}-{{b}_{2}}^{2}}\]

If the equation of the locus of a point equidistant from the points (\

1.	If the equation of the locus of a point equidistant from the points (\[{{a}_{1,}}{{b}_{1}}\]) and (\[{{a}_{2,}}{{b}_{2}}\]) is (\[{{a}_{1,-}}{{a}_{2}}\])x+(\[{{b}_{1,-}}{{b}_{2}}\])\[y+c=0\] then the value of c is
A.	\[\frac{1}{2}({{a}_{2}}^{2}+{{b}_{2}}^{2}-{{a}_{1}}^{2}-{{b}_{1}}^{2})\]
B.	\[{{a}_{1}}^{2}+{{a}_{2}}^{2}+{{b}_{1}}^{2}-{{b}_{2}}^{2}\]
C.	\[\frac{1}{2}({{a}_{1}}^{2}+{{a}_{2}}^{2}-{{b}_{1}}^{2}-{{b}_{2}}^{2})\]
D.	\[\sqrt{{{a}_{1}}^{2}+{{b}_{2}}^{2}-{{a}_{2}}^{2}-{{b}_{2}}^{2}}\]
Answer» B. \[{{a}_{1}}^{2}+{{a}_{2}}^{2}+{{b}_{1}}^{2}-{{b}_{2}}^{2}\]

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If the equation of the locus of a point equidistant from the points (\[{{a}_{1,}}{{b}_{1}}\]) and (\[{{a}_{2,}}{{b}_{2}}\]) is (\[{{a}_{1,-}}{{a}_{2}}\])x+(\[{{b}_{1,-}}{{b}_{2}}\])\[y+c=0\] then the value of c is

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