MCQOPTIONS
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| 1. |
If the equation for the displacement of a particle moving on a circular path is given by \[(\theta )=2{{t}^{3}}+0.5\], where \[\theta \] is in radians and \[t\] in seconds, then the angular velocity of the particle after 2 sec from its start is [AIIMS 1998] |
| A. | 8 rad/sec |
| B. | 12 rad/sec |
| C. | 24 rad/sec |
| D. | 36 rad/sec |
| Answer» D. 36 rad/sec | |