MCQOPTIONS
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| 1. |
If the electron revolving around the nucleus in a radius 'r' with orbital speed 'v' has magnetic moment evr/2. Hence, using Bohr's postulate of the quantization of angular momentum obtain the magnetic moment (M) of hydrogen atom in its ground state and current (I) due to revolution of electron. |
| A. | \[M=\frac{eh}{4\pi m},I=\frac{eV}{2\pi r}\] |
| B. | \[M=\frac{2eh}{5\pi m},I=\frac{eV}{4\pi r}\] |
| C. | \[M=\frac{h}{\pi m},I=\frac{e}{\pi r}\] |
| D. | \[M=\frac{eh}{\pi m},I=\frac{eV}{\pi r}\] |
| Answer» B. \[M=\frac{2eh}{5\pi m},I=\frac{eV}{4\pi r}\] | |