If the eccentricity of the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}+1}+\frac{{{y}^{2}}}{{{a}^{2}}+2}=1\] Is \[1\sqrt{6}\], then the latus rectum of the ellipse is

If the eccentricity of the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}+1}+\fr

1.	If the eccentricity of the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}+1}+\frac{{{y}^{2}}}{{{a}^{2}}+2}=1\] Is \[1\sqrt{6}\], then the latus rectum of the ellipse is
A.	\[5/\sqrt{6}\]
B.	\[10/\sqrt{6}\]
C.	\[8/\sqrt{6}\]
D.	None of these
Answer» C. \[8/\sqrt{6}\]

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If the eccentricity of the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}+1}+\frac{{{y}^{2}}}{{{a}^{2}}+2}=1\] Is \[1\sqrt{6}\], then the latus rectum of the ellipse is

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