1.

If the cube roots of unity be \[1,\omega ,{{\omega }^{2}},\] then the roots of the equation \[{{(x-1)}^{3}}+8=0\]are [IIT 1979; MNR 1986; DCE 2000; AIEEE 2005]

A. \[-1,\,1+2\omega ,\,1+2{{\omega }^{2}}\]
B. \[-1,\,1-2\omega ,\,1-2{{\omega }^{2}}\]
C. \[-1,\,-1,\,-1\]
D. None of these
Answer» C. \[-1,\,-1,\,-1\]


Discussion

No Comment Found