MCQOPTIONS
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| 1. |
If the circle \[{{x}^{2}}+{{y}^{2}}=4\]bisects the circumference of the circle \[{{x}^{2}}+{{y}^{2}}-2x+6y+a=0\], then a equals [RPET 1999] |
| A. | 4 |
| B. | -4 |
| C. | 16 |
| D. | -16 |
| Answer» D. -16 | |