If the centre of a circle is (2, 3) and a tangent is \[x+y=1\], then the equation of this circle is [RPET 1985, 89]

\[{{(x-2)}^{2}}+{{(y-3)}^{2}}=3\]

\[{{(x-2)}^{2}}+{{(y-3)}^{2}}=8\]

\[{{(x+2)}^{2}}+{{(y+3)}^{2}}=2\sqrt{2}\]

\[{{(x-2)}^{2}}+{{(y-3)}^{2}}=2\sqrt{2}\]

If the centre of a circle is (2, 3) and a tangent is \[x+y=1\], then t

1.	If the centre of a circle is (2, 3) and a tangent is \[x+y=1\], then the equation of this circle is [RPET 1985, 89]
A.	\[{{(x-2)}^{2}}+{{(y-3)}^{2}}=8\]
B.	\[{{(x-2)}^{2}}+{{(y-3)}^{2}}=3\]
C.	\[{{(x+2)}^{2}}+{{(y+3)}^{2}}=2\sqrt{2}\]
D.	\[{{(x-2)}^{2}}+{{(y-3)}^{2}}=2\sqrt{2}\]
Answer» B. \[{{(x-2)}^{2}}+{{(y-3)}^{2}}=3\]

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If the centre of a circle is (2, 3) and a tangent is \[x+y=1\], then the equation of this circle is [RPET 1985, 89]

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