If the average of x and $$\frac{1}{x}$$ (x $$ \ne $$ 0) is M, then the average of x2and $$\frac{1}{{{x^2}}}$$is :

If the average of x and $$\frac{1}{x}$$ (x $$ \ne $$ 0) is M, then the

1.	If the average of x and $$\frac{1}{x}$$ (x $$ \ne $$ 0) is M, then the average of x2and $$\frac{1}{{{x^2}}}$$is :
A.	- M2
B.	- 2M2
C.	M2- 1
D.	M2+ 1
Answer» D. M2+ 1

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If the average of x and $$\frac{1}{x}$$ (x $$ \ne $$ 0) is M, then the average of x2and $$\frac{1}{{{x^2}}}$$is :

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