MCQOPTIONS
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| 1. |
If \[\tan y=\frac{2t}{1-{{t}^{2}}}\]and \[\sin x=\frac{2t}{1+{{t}^{2}}},\]then \[\frac{dy}{dx}=\] |
| A. | \[\frac{2}{1+{{t}^{2}}}\] |
| B. | \[\frac{1}{1+{{t}^{2}}}\] |
| C. | 1 |
| D. | 2 |
| Answer» D. 2 | |