If \[\tan \theta =\frac{x\,\sin \,\varphi }{1-x\,\cos \,\varphi }\] and \[\tan \,\varphi =\frac{y\sin \,\theta }{1-y\,\cos \,\theta }\], then \[\frac{x}{y}=\] [MP PET 1991]

\[\frac{\sin \varphi }{1-\cos \theta }\]

\[\frac{\sin \varphi }{\sin \theta }\]

\[\frac{\sin \theta }{\sin \varphi }\]

\[\frac{\sin \theta }{1-\cos \varphi }\]

If \[\tan \theta =\frac{x\,\sin \,\varphi }{1-x\,\cos \,\varphi }\] an

1.	If \[\tan \theta =\frac{x\,\sin \,\varphi }{1-x\,\cos \,\varphi }\] and \[\tan \,\varphi =\frac{y\sin \,\theta }{1-y\,\cos \,\theta }\], then \[\frac{x}{y}=\] [MP PET 1991]
A.	\[\frac{\sin \varphi }{\sin \theta }\]
B.	\[\frac{\sin \theta }{\sin \varphi }\]
C.	\[\frac{\sin \varphi }{1-\cos \theta }\]
D.	\[\frac{\sin \theta }{1-\cos \varphi }\]
Answer» C. \[\frac{\sin \varphi }{1-\cos \theta }\]

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If \[\tan \theta =\frac{x\,\sin \,\varphi }{1-x\,\cos \,\varphi }\] and \[\tan \,\varphi =\frac{y\sin \,\theta }{1-y\,\cos \,\theta }\], then \[\frac{x}{y}=\] [MP PET 1991]

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