If \[\tan \frac{A}{2}=\frac{3}{2},\]then \[\frac{1+\cos A}{1-\cos A}=\

1.	If \[\tan \frac{A}{2}=\frac{3}{2},\]then \[\frac{1+\cos A}{1-\cos A}=\]
A.	\[-5\]
B.	\[5\]
C.	\[9/4\]
D.	\[4/9\]
Answer» E.

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If \[\tan \frac{A}{2}=\frac{3}{2},\]then \[\frac{1+\cos A}{1-\cos A}=\]

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