If \[{{\tan }^{-1}}(x-1)+{{\tan }^{-1}}x+{{\tan }^{-1}}(x+1)={{\tan }^{-1}}3x\],then x =

If \[{{\tan }^{-1}}(x-1)+{{\tan }^{-1}}x+{{\tan }^{-1}}(x+1)={{\tan

1.	If \[{{\tan }^{-1}}(x-1)+{{\tan }^{-1}}x+{{\tan }^{-1}}(x+1)={{\tan }^{-1}}3x\],then x =
A.	\[\pm \frac{1}{2}\]
B.	\[0,\,\frac{1}{2}\]
C.	\[0,\,-\frac{1}{2}\]
D.	\[0,\,\pm \frac{1}{2}\]
Answer» E.

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If \[{{\tan }^{-1}}(x-1)+{{\tan }^{-1}}x+{{\tan }^{-1}}(x+1)={{\tan }^{-1}}3x\],then x =

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