If \[{{\tan }^{-1}}\frac{x-1}{x+2}+{{\tan }^{-1}}\frac{x+1}{x+2}=\frac{\pi }{4}\], then x =

If \[{{\tan }^{-1}}\frac{x-1}{x+2}+{{\tan }^{-1}}\frac{x+1}{x+2}=\frac

1.	If \[{{\tan }^{-1}}\frac{x-1}{x+2}+{{\tan }^{-1}}\frac{x+1}{x+2}=\frac{\pi }{4}\], then x =
A.	\[\frac{1}{\sqrt{2}}\]
B.	\[-\frac{1}{\sqrt{2}}\]
C.	\[\pm \sqrt{\frac{5}{2}}\]
D.	\[\pm \frac{1}{2}\]
Answer» D. \[\pm \frac{1}{2}\]

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If \[{{\tan }^{-1}}\frac{x-1}{x+2}+{{\tan }^{-1}}\frac{x+1}{x+2}=\frac{\pi }{4}\], then x =

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