If \[{{\tan }^{-1}}\frac{x-1}{x+1}+{{\tan }^{-1}}\frac{2x-1}{2x+1}={{\tan }^{-1}}\frac{23}{36},\]then x = [ISM Dhanbad 1973]

If \[{{\tan }^{-1}}\frac{x-1}{x+1}+{{\tan }^{-1}}\frac{2x-1}{2x+1}={{\

1.	If \[{{\tan }^{-1}}\frac{x-1}{x+1}+{{\tan }^{-1}}\frac{2x-1}{2x+1}={{\tan }^{-1}}\frac{23}{36},\]then x = [ISM Dhanbad 1973]
A.	\[\frac{3}{4},\frac{-3}{8}\]
B.	\[\frac{3}{4},\frac{3}{8}\]
C.	\[\frac{4}{3},\frac{3}{8}\]
D.	None of these
Answer» E.

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If \[{{\tan }^{-1}}\frac{x-1}{x+1}+{{\tan }^{-1}}\frac{2x-1}{2x+1}={{\tan }^{-1}}\frac{23}{36},\]then x = [ISM Dhanbad 1973]

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