If \[{{\tan }^{-1}}\frac{a+x}{a}+{{\tan }^{-1}}\frac{a-x}{a}=\frac{\pi }{6}\],then \[{{x}^{2}}\]=

If \[{{\tan }^{-1}}\frac{a+x}{a}+{{\tan }^{-1}}\frac{a-x}{a}=\frac{\pi

1.	If \[{{\tan }^{-1}}\frac{a+x}{a}+{{\tan }^{-1}}\frac{a-x}{a}=\frac{\pi }{6}\],then \[{{x}^{2}}\]=
A.	\[2\sqrt{3}a\]
B.	\[\sqrt{3}a\]
C.	\[2\sqrt{3}{{a}^{2}}\]
D.	None of these
Answer» D. None of these

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If \[{{\tan }^{-1}}\frac{a+x}{a}+{{\tan }^{-1}}\frac{a-x}{a}=\frac{\pi }{6}\],then \[{{x}^{2}}\]=

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