If \[{{\tan }^{-1}}\frac{1-x}{1+x}=\frac{1}{2}{{\tan }^{-1}}x\], then x =

If \[{{\tan }^{-1}}\frac{1-x}{1+x}=\frac{1}{2}{{\tan }^{-1}}x\], then

1.	If \[{{\tan }^{-1}}\frac{1-x}{1+x}=\frac{1}{2}{{\tan }^{-1}}x\], then x =
A.	1
B.	\[\sqrt{3}\]
C.	\[\frac{1}{\sqrt{3}}\]
D.	None of these
Answer» D. None of these

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If \[{{\tan }^{-1}}\frac{1-x}{1+x}=\frac{1}{2}{{\tan }^{-1}}x\], then x =

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