If \[{{\tan }^{-1}}2x+{{\tan }^{-1}}3x=\frac{\pi }{4}\], then x = [Roorkee 1978, 80; MNR 1986; Pb. CET 2001; Karnataka CET 2002]

If \[{{\tan }^{-1}}2x+{{\tan }^{-1}}3x=\frac{\pi }{4}\], then x = [Roo

1.	If \[{{\tan }^{-1}}2x+{{\tan }^{-1}}3x=\frac{\pi }{4}\], then x = [Roorkee 1978, 80; MNR 1986; Pb. CET 2001; Karnataka CET 2002]
A.	-1
B.	\[\frac{1}{6}\]
C.	\[-1,\,\frac{1}{6}\]
D.	None of these
Answer» C. \[-1,\,\frac{1}{6}\]

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If \[{{\tan }^{-1}}2x+{{\tan }^{-1}}3x=\frac{\pi }{4}\], then x = [Roorkee 1978, 80; MNR 1986; Pb. CET 2001; Karnataka CET 2002]

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