If \[{{\tan }^{-1}}(2x)+ta{{n}^{-1}}(3x)=\frac{\pi }{4}\]then x is equal to

If \[{{\tan }^{-1}}(2x)+ta{{n}^{-1}}(3x)=\frac{\pi }{4}\]then x is equ

1.	If \[{{\tan }^{-1}}(2x)+ta{{n}^{-1}}(3x)=\frac{\pi }{4}\]then x is equal to
A.	-1
B.	-2
C.	1
D.	2
Answer» B. -2

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If \[{{\tan }^{-1}}(2x)+ta{{n}^{-1}}(3x)=\frac{\pi }{4}\]then x is equal to

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