If t and T are the number of teeth on pinion and gear, G is gear ratio, Ap is the fraction by which the standard addendum of one module is multiplied and ϕ is the pressure angle, the expression of the minimum number of teeth on the pinion to avoid interference when pinion and gear have an equal number of teeth is given as

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$t = \frac{{2{A_p}}}{{\sqrt {1~- ~3\;Si{n^2}\phi } ~ +~ 1}}$

TuteeHUB · Answer

$t = \frac{{2{A_p}}}{{\sqrt {1~ +~ 3\;Si{n^2}\phi } ~+ ~1}}$

TuteeHUB · Answer

$t = \frac{{2{A_p}}}{{\sqrt {1~ -~ 3\;Si{n^2}\phi } ~ - ~1}}$

TuteeHUB · Answer

$t = \frac{{2{A_p}}}{{\sqrt {1 ~+~ 3\;Si{n^2}\phi } ~-~ 1}}$

1.	If t and T are the number of teeth on pinion and gear, G is gear ratio, Ap is the fraction by which the standard addendum of one module is multiplied and ϕ is the pressure angle, the expression of the minimum number of teeth on the pinion to avoid interference when pinion and gear have an equal number of teeth is given as
A.	\(t = \frac{{2{A_p}}}{{\sqrt {1~- ~3\;Si{n^2}\phi } ~ +~ 1}}\)
B.	\(t = \frac{{2{A_p}}}{{\sqrt {1~ +~ 3\;Si{n^2}\phi } ~+ ~1}}\)
C.	\(t = \frac{{2{A_p}}}{{\sqrt {1~ -~ 3\;Si{n^2}\phi } ~ - ~1}}\)
D.	\(t = \frac{{2{A_p}}}{{\sqrt {1 ~+~ 3\;Si{n^2}\phi } ~-~ 1}}\)
Answer» E.

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