If \[\sum\nolimits_{i=1}^{9}{({{x}_{i}}-5)=9}\] and \[\sum\nolimits_{i=1}^{9}{{{({{x}_{i}}-5)}^{2}}=45,}\] then the standard deviation of the 9 items \[{{x}_{1}},{{x}_{2}},...{{x}_{9}}\] is

If \[\sum\nolimits_{i=1}^{9}{({{x}_{i}}-5)=9}\] and \[\sum\nolimits_{i

1.	If \[\sum\nolimits_{i=1}^{9}{({{x}_{i}}-5)=9}\] and \[\sum\nolimits_{i=1}^{9}{{{({{x}_{i}}-5)}^{2}}=45,}\] then the standard deviation of the 9 items \[{{x}_{1}},{{x}_{2}},...{{x}_{9}}\] is
A.	9
B.	4
C.	3
D.	2
Answer» E.

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If \[\sum\nolimits_{i=1}^{9}{({{x}_{i}}-5)=9}\] and \[\sum\nolimits_{i=1}^{9}{{{({{x}_{i}}-5)}^{2}}=45,}\] then the standard deviation of the 9 items \[{{x}_{1}},{{x}_{2}},...{{x}_{9}}\] is

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