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1. |
If $$\sqrt {{\text{4096}}} $$= 64, then the value of $$\sqrt {{\text{40}}{\text{.96}}} $$$$ + $$$$\sqrt {{\text{0}}{\text{.4096}}} $$$$ + $$ $$\sqrt {{\text{0}}{\text{.004096}}} $$$$ + $$ $$\sqrt {{\text{0}}{\text{.00004096}}} $$up to two place of decimals is = ? |
A. | 0.09 |
B. | 0.1 |
C. | 0.11 |
D. | 0.12 |
Answer» D. 0.12 | |