If \[\sqrt{(1-{{x}^{6}})}+\sqrt{(1-{{y}^{6}})}={{a}^{3}}({{x}^{3}}-{{y}^{3}})\], then \[\frac{dy}{dx}=\] [Roorkee 1994]

\[\frac{{{x}^{2}}}{{{y}^{2}}}\sqrt{\frac{1-{{x}^{6}}}{1-{{y}^{6}}}}\]

\[\frac{{{y}^{2}}}{{{x}^{2}}}\sqrt{\frac{1-{{y}^{6}}}{1-{{x}^{6}}}}\]

\[\frac{{{x}^{2}}}{{{y}^{2}}}\sqrt{\frac{1-{{y}^{6}}}{1-{{x}^{6}}}}\]

If \[\sqrt{(1-{{x}^{6}})}+\sqrt{(1-{{y}^{6}})}={{a}^{3}}({{x}^{3}}-{{y

1.	If \[\sqrt{(1-{{x}^{6}})}+\sqrt{(1-{{y}^{6}})}={{a}^{3}}({{x}^{3}}-{{y}^{3}})\], then \[\frac{dy}{dx}=\] [Roorkee 1994]
A.	\[\frac{{{x}^{2}}}{{{y}^{2}}}\sqrt{\frac{1-{{x}^{6}}}{1-{{y}^{6}}}}\]
B.	\[\frac{{{y}^{2}}}{{{x}^{2}}}\sqrt{\frac{1-{{y}^{6}}}{1-{{x}^{6}}}}\]
C.	\[\frac{{{x}^{2}}}{{{y}^{2}}}\sqrt{\frac{1-{{y}^{6}}}{1-{{x}^{6}}}}\]
D.	None of these
Answer» D. None of these

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If \[\sqrt{(1-{{x}^{6}})}+\sqrt{(1-{{y}^{6}})}={{a}^{3}}({{x}^{3}}-{{y}^{3}})\], then \[\frac{dy}{dx}=\] [Roorkee 1994]

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