If \[\sin \theta +\cos \theta =x,\] then \[{{\sin }^{6}}\theta +{{\cos }^{6}}\theta =\frac{1}{4}[4-3{{({{x}^{2}}-1)}^{2}}]\] for

If \[\sin \theta +\cos \theta =x,\] then \[{{\sin }^{6}}\theta +{{\cos

1.	If \[\sin \theta +\cos \theta =x,\] then \[{{\sin }^{6}}\theta +{{\cos }^{6}}\theta =\frac{1}{4}[4-3{{({{x}^{2}}-1)}^{2}}]\] for
A.	All real x
B.	\[{{x}^{2}}\le 2\]
C.	\[{{x}^{2}}\ge 2\]
D.	None of these
Answer» C. \[{{x}^{2}}\ge 2\]

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If \[\sin \theta +\cos \theta =x,\] then \[{{\sin }^{6}}\theta +{{\cos }^{6}}\theta =\frac{1}{4}[4-3{{({{x}^{2}}-1)}^{2}}]\] for

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