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1. |
If \[\sin (\theta +\alpha )=a\] and \[\sin (\theta +\beta )=b,\] then \[\cos 2\,(\alpha -\beta )-4ab\,\cos (\alpha -\beta )\] is equal to |
A. | \[1-{{a}^{2}}-{{b}^{2}}\] |
B. | \[1-2{{a}^{2}}-2{{b}^{2}}\] |
C. | \[2+{{a}^{2}}+{{b}^{2}}\] |
D. | \[2-{{a}^{2}}-{{b}^{2}}\] |
Answer» C. \[2+{{a}^{2}}+{{b}^{2}}\] | |