1.

If \[\sin (\theta +\alpha )=a\] and \[\sin (\theta +\beta )=b,\] then \[\cos 2\,(\alpha -\beta )-4ab\,\cos (\alpha -\beta )\] is equal to

A. \[1-{{a}^{2}}-{{b}^{2}}\]
B. \[1-2{{a}^{2}}-2{{b}^{2}}\]
C. \[2+{{a}^{2}}+{{b}^{2}}\]
D. \[2-{{a}^{2}}-{{b}^{2}}\]
Answer» C. \[2+{{a}^{2}}+{{b}^{2}}\]


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