If \[\sin {{\theta }_{1}}+\sin {{\theta }_{2}}+\sin {{\theta }_{3}}=3,\]then \[\cos {{\theta }_{1}}+\cos {{\theta }_{2}}+\cos {{\theta }_{3}}=\] [EAMCET 1994]

If \[\sin {{\theta }_{1}}+\sin {{\theta }_{2}}+\sin {{\theta }_{3}}=3,

1.	If \[\sin {{\theta }_{1}}+\sin {{\theta }_{2}}+\sin {{\theta }_{3}}=3,\]then \[\cos {{\theta }_{1}}+\cos {{\theta }_{2}}+\cos {{\theta }_{3}}=\] [EAMCET 1994]
A.	3
B.	2
C.	1
D.	0
Answer» E.

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If \[\sin {{\theta }_{1}}+\sin {{\theta }_{2}}+\sin {{\theta }_{3}}=3,\]then \[\cos {{\theta }_{1}}+\cos {{\theta }_{2}}+\cos {{\theta }_{3}}=\] [EAMCET 1994]

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