If \[\sin ({{\cot }^{-1}}(x+1)=\cos ({{\tan }^{-1}}x)\], then x = [IIT Screening 2004]

If \[\sin ({{\cot }^{-1}}(x+1)=\cos ({{\tan }^{-1}}x)\], then x = [IIT

1.	If \[\sin ({{\cot }^{-1}}(x+1)=\cos ({{\tan }^{-1}}x)\], then x = [IIT Screening 2004]
A.	\[-\frac{1}{2}\]
B.	\[\frac{1}{2}\]
C.	0
D.	\[\frac{9}{4}\]
Answer» B. \[\frac{1}{2}\]

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If \[\sin ({{\cot }^{-1}}(x+1)=\cos ({{\tan }^{-1}}x)\], then x = [IIT Screening 2004]

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