1.

If \[\sin 6\theta =32{{\cos }^{5}}\theta \sin \theta -32{{\cos }^{3}}\theta \sin \theta +3x,\] then \[x=\] [EAMCET 2003]

A. \[\cos \theta \]
B. \[\cos 2\theta \]
C. \[\sin \theta \]
D. \[\sin 2\theta \]
Answer» E.


Discussion

No Comment Found