If \[{{\sin }^{-1}}x+{{\cot }^{-1}}\left( \frac{1}{2} \right)=\frac{\pi }{2},\]then x is [Roorkee 1999; Karnataka CET 1999]

If \[{{\sin }^{-1}}x+{{\cot }^{-1}}\left( \frac{1}{2} \right)=\frac{\p

1.	If \[{{\sin }^{-1}}x+{{\cot }^{-1}}\left( \frac{1}{2} \right)=\frac{\pi }{2},\]then x is [Roorkee 1999; Karnataka CET 1999]
A.	0
B.	\[\frac{1}{\sqrt{5}}\]
C.	\[\frac{2}{\sqrt{5}}\]
D.	\[\frac{\sqrt{3}}{2}\]
Answer» C. \[\frac{2}{\sqrt{5}}\]

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If \[{{\sin }^{-1}}x+{{\cot }^{-1}}\left( \frac{1}{2} \right)=\frac{\pi }{2},\]then x is [Roorkee 1999; Karnataka CET 1999]

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