1.

If \[{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)+{{\sin }^{-1}}\left( \frac{2b}{1+{{b}^{2}}} \right)=2{{\tan }^{-1}}x,\]then \[x=\]        [MNR 1984; UPSEAT 1999; Pb. CET 2004]

A. \[\frac{a-b}{1+ab}\]
B. \[\frac{b}{1+ab}\]
C. \[\frac{b}{1-ab}\]
D. \[\frac{a+b}{1-ab}\]
Answer» E.


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