If \[{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)-{{\cos }^{-1}}\left( \frac{1-{{b}^{2}}}{1+{{b}^{2}}} \right)={{\tan }^{-1}}\left( \frac{2x}{1-{{x}^{2}}} \right),\]then what is the value of x?

If \[{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)-{{\cos }^{-1}

1.	If \[{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)-{{\cos }^{-1}}\left( \frac{1-{{b}^{2}}}{1+{{b}^{2}}} \right)={{\tan }^{-1}}\left( \frac{2x}{1-{{x}^{2}}} \right),\]then what is the value of x?
A.	\[a/b\]
B.	\[ab\]
C.	\[b/a\]
D.	\[\frac{a-b}{1+ab}\]
Answer» E.

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If \[{{\sin }^{-1}}\left( \frac{2a}{1+{{a}^{2}}} \right)-{{\cos }^{-1}}\left( \frac{1-{{b}^{2}}}{1+{{b}^{2}}} \right)={{\tan }^{-1}}\left( \frac{2x}{1-{{x}^{2}}} \right),\]then what is the value of x?

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