If \[{{\sin }^{-1}}\frac{x}{5}+\text{cose}{{\text{c}}^{-1}}\left( \frac{5}{4} \right)=\frac{\pi }{2},\]then \[x=\] [EAMCET 1983; Karnataka CET 2004]

If \[{{\sin }^{-1}}\frac{x}{5}+\text{cose}{{\text{c}}^{-1}}\left( \fra

1.	If \[{{\sin }^{-1}}\frac{x}{5}+\text{cose}{{\text{c}}^{-1}}\left( \frac{5}{4} \right)=\frac{\pi }{2},\]then \[x=\] [EAMCET 1983; Karnataka CET 2004]
A.	4
B.	5
C.	1
D.	3
Answer» E.

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If \[{{\sin }^{-1}}\frac{x}{5}+\text{cose}{{\text{c}}^{-1}}\left( \frac{5}{4} \right)=\frac{\pi }{2},\]then \[x=\] [EAMCET 1983; Karnataka CET 2004]

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