If \[{{\sin }^{-1}}\frac{1}{x}={{\sin }^{-1}}\frac{1}{a}+{{\sin }^{-1}}\frac{1}{b},\] then the value of x is

\[\frac{ab}{\sqrt{{{a}^{2}}-1}-\sqrt{{{b}^{2}}-1}}\]

\[\frac{ab}{\sqrt{{{a}^{2}}-1}+\sqrt{{{b}^{2}}-1}}\]

\[\frac{2ab}{\sqrt{{{a}^{2}}-1}+\sqrt{{{b}^{2}}-1}}\]

If \[{{\sin }^{-1}}\frac{1}{x}={{\sin }^{-1}}\frac{1}{a}+{{\sin }^{-1}

1.	If \[{{\sin }^{-1}}\frac{1}{x}={{\sin }^{-1}}\frac{1}{a}+{{\sin }^{-1}}\frac{1}{b},\] then the value of x is
A.	\[\frac{ab}{\sqrt{{{a}^{2}}-1}+\sqrt{{{b}^{2}}-1}}\]
B.	\[\frac{ab}{\sqrt{{{a}^{2}}-1}-\sqrt{{{b}^{2}}-1}}\]
C.	\[\frac{2ab}{\sqrt{{{a}^{2}}-1}+\sqrt{{{b}^{2}}-1}}\]
D.	None of these
Answer» B. \[\frac{ab}{\sqrt{{{a}^{2}}-1}-\sqrt{{{b}^{2}}-1}}\]

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If \[{{\sin }^{-1}}\frac{1}{x}={{\sin }^{-1}}\frac{1}{a}+{{\sin }^{-1}}\frac{1}{b},\] then the value of x is

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