If \[{{\sin }^{-1}}\frac{1}{3}+{{\sin }^{-1}}\frac{2}{3}={{\sin }^{-1}}x,\]then x is equal to [Roorkee 1995]

\[\frac{\sqrt{5}-4\sqrt{2}}{9}\]

\[\frac{\sqrt{5}+4\sqrt{2}}{9}\]

If \[{{\sin }^{-1}}\frac{1}{3}+{{\sin }^{-1}}\frac{2}{3}={{\sin }^{-1}

1.	If \[{{\sin }^{-1}}\frac{1}{3}+{{\sin }^{-1}}\frac{2}{3}={{\sin }^{-1}}x,\]then x is equal to [Roorkee 1995]
A.	0
B.	\[\frac{\sqrt{5}-4\sqrt{2}}{9}\]
C.	\[\frac{\sqrt{5}+4\sqrt{2}}{9}\]
D.	\[\frac{\pi }{2}\]
Answer» D. \[\frac{\pi }{2}\]

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If \[{{\sin }^{-1}}\frac{1}{3}+{{\sin }^{-1}}\frac{2}{3}={{\sin }^{-1}}x,\]then x is equal to [Roorkee 1995]

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