If \[{{\sin }^{-1}}\frac{1}{2}={{\tan }^{-1}}x,\]then x =

1.	If \[{{\sin }^{-1}}\frac{1}{2}={{\tan }^{-1}}x,\]then x =
A.	\[\sqrt{3}\]
B.	\[\frac{1}{\sqrt{3}}\]
C.	\[\frac{1}{\sqrt{2}}\]
D.	None of these
Answer» C. \[\frac{1}{\sqrt{2}}\]

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If \[{{\sin }^{-1}}\frac{1}{2}={{\tan }^{-1}}x,\]then x =

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