If sec θ and sin θ (0 < θ < 90) are the roots of the equation \(\sqrt{6} x^2 - kx + \sqrt{6}=0\), then the value of k is:

• A. \(2\sqrt{3}\)
• B. \(3\sqrt{2}\)
• C. \(\sqrt{3}\)
• D. \(3\sqrt{3}\)