If \[s=\sqrt{{{t}^{2}}+1}\], then \[\frac{{{d}^{2}}s}{d{{t}^{2}}}\] is equal to

If \[s=\sqrt{{{t}^{2}}+1}\], then \[\frac{{{d}^{2}}s}{d{{t}^{2}}}\] is

1.	If \[s=\sqrt{{{t}^{2}}+1}\], then \[\frac{{{d}^{2}}s}{d{{t}^{2}}}\] is equal to
A.	\[\frac{1}{s}\]
B.	\[\frac{1}{{{s}^{2}}}\]
C.	\[\frac{1}{{{s}^{3}}}\]
D.	\[\frac{1}{{{s}^{4}}}\]
Answer» D. \[\frac{1}{{{s}^{4}}}\]

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If \[s=\sqrt{{{t}^{2}}+1}\], then \[\frac{{{d}^{2}}s}{d{{t}^{2}}}\] is equal to

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