If \[{{S}_{n}}=\sum\limits_{k=1}^{n}{{{a}_{k}}}\]and\[\underset{n\to \infty }{\mathop{\lim }}\,{{a}_{n}}=a,\]then \[\underset{n\to \infty }{\mathop{\lim }}\,\frac{{{S}_{n+1}}-{{S}_{n}}}{\sqrt{\sum\limits_{k=1}^{n}{k}}}\]is equal to

If \[{{S}_{n}}=\sum\limits_{k=1}^{n}{{{a}_{k}}}\]and\[\underset{n\to \

1.	If \[{{S}_{n}}=\sum\limits_{k=1}^{n}{{{a}_{k}}}\]and\[\underset{n\to \infty }{\mathop{\lim }}\,{{a}_{n}}=a,\]then \[\underset{n\to \infty }{\mathop{\lim }}\,\frac{{{S}_{n+1}}-{{S}_{n}}}{\sqrt{\sum\limits_{k=1}^{n}{k}}}\]is equal to
A.	0
B.	a
C.	\[\sqrt{2}a\]
D.	\[2a\]
Answer» B. a

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If \[{{S}_{n}}=\sum\limits_{k=1}^{n}{{{a}_{k}}}\]and\[\underset{n\to \infty }{\mathop{\lim }}\,{{a}_{n}}=a,\]then \[\underset{n\to \infty }{\mathop{\lim }}\,\frac{{{S}_{n+1}}-{{S}_{n}}}{\sqrt{\sum\limits_{k=1}^{n}{k}}}\]is equal to

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