If \({\rm{z}} = {\rm{}} - \frac{{2\left( {1\; + \;2{\rm{i}}} \right)}}{{3\; + \;{\rm{i}}}}\) Where \(i = \sqrt { - 1}\) then the argument θ (-π < θ ≤ π) of z is

If \({\rm{z}} = {\rm{}} - \frac{{2\left( {1\; + \;2{\rm{i}}} \right)}}

1.	If \({\rm{z}} = {\rm{}} - \frac{{2\left( {1\; + \;2{\rm{i}}} \right)}}{{3\; + \;{\rm{i}}}}\) Where \(i = \sqrt { - 1}\) then the argument θ (-π < θ ≤ π) of z is
A.	\(\frac{{3\pi }}{4}\)
B.	\(\frac{\pi }{4}\)
C.	\(\frac{{5\pi }}{6}\)
D.	\(- \frac{{3\pi }}{4}\)
Answer» E.