If $\rm \overline{X}_1$ and $\rm \overline{X}_2$ are the means of two distributions such that $\rm \overline{X}_1

Question

If $\rm \overline{X}_1$ and $\rm \overline{X}_2$ are the means of two distributions such that $\rm \overline{X}_1 < \rm \overline{X}_2$, and $\rm \overline{X}$ is the mean of the combined distribution, then:

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\rm \overline{X} < \rm \overline{X}_1$

TuteeHUB · Answer

$\rm \overline{X} > \rm \overline{X}_2$

TuteeHUB · Answer

$\rm \overline{X}= \dfrac{\overline{X}_1+\overline{X}_2}{2}$

TuteeHUB · Answer

$\rm \overline{X}_1 < \overline{X} < \rm \overline{X}_2$

1.	If \(\rm \overline{X}_1\) and \(\rm \overline{X}_2\) are the means of two distributions such that \(\rm \overline{X}_1 < \rm \overline{X}_2\), and \(\rm \overline{X}\) is the mean of the combined distribution, then:
A.	\(\rm \overline{X} < \rm \overline{X}_1\)
B.	\(\rm \overline{X} > \rm \overline{X}_2\)
C.	\(\rm \overline{X}= \dfrac{\overline{X}_1+\overline{X}_2}{2}\)
D.	\(\rm \overline{X}_1 < \overline{X} < \rm \overline{X}_2\)
Answer» E.

If \(\rm \overline{X}_1\) and \(\rm \overline{X}_2\) are the means of two distributions such that \(\rm \overline{X}_1 < \rm \overline{X}_2\), and \(\rm \overline{X}\) is the mean of the combined distribution, then:

Discussion

No Comment Found

Related MCQs

Reply to Comment