1.

If radiation corresponding to first line of "Balmer series" of \[H{{e}^{+}}\] ion knocked out electron from 1st excited state of H atom, the kinetic energy of ejected electron from H atom would be (eV) - [Given \[{{E}_{n}}=-\frac{{{Z}^{2}}}{{{n}^{2}}}\left( 13.6eV \right)\]]

A.  4.155 eV
B.  8.310 eV
C.  2.515 eV
D.  5.550 eV
Answer» B.  8.310 eV


Discussion

No Comment Found

Related MCQs