1.

If q is the punching shear resistance per unit area, a is the side of square footing for a column side b, carrying a weight W including the weight of footing, the depth of footing (D) considering the punching shear resistance is

A. \(D = \frac{W(a-b)}{4a^2bq}\)
B. \(D = \frac{W(a^2-b^2)}{4a^2bq}\)
C. \(D = \frac{W(a^2-b^2)}{8a^2bq}\)
D. \(D = \frac{W(a^2-b^2)}{4abq}\)
Answer» C. \(D = \frac{W(a^2-b^2)}{8a^2bq}\)


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