If \[\pi \le x\le 2\pi \], then \[{{\cos }^{-1}}(\cos x)\]is equal to

1.	If \[\pi \le x\le 2\pi \], then \[{{\cos }^{-1}}(\cos x)\]is equal to
A.	x
B.	\[-x\]
C.	\[2\pi +x\]
D.	\[2\pi -x\]
Answer» E.

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If \[\pi \le x\le 2\pi \], then \[{{\cos }^{-1}}(\cos x)\]is equal to

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