If \[P=n({{n}^{2}}-{{1}^{2}})({{n}^{2}}-{{2}^{2}})({{n}^{2}}-{{3}^{2}})...({{n}^{2}}-{{r}^{2}}),\] \[n>r,n\in N\] then P is necessarily divisible by

If \[P=n({{n}^{2}}-{{1}^{2}})({{n}^{2}}-{{2}^{2}})({{n}^{2}}-{{3}^{2}}

1.	If \[P=n({{n}^{2}}-{{1}^{2}})({{n}^{2}}-{{2}^{2}})({{n}^{2}}-{{3}^{2}})...({{n}^{2}}-{{r}^{2}}),\] \[n>r,n\in N\] then P is necessarily divisible by
A.	\[(2r+2)!\]
B.	\[(2r+4)!\]
C.	\[(2r+1)!\]
D.	None of these
Answer» D. None of these

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If \[P=n({{n}^{2}}-{{1}^{2}})({{n}^{2}}-{{2}^{2}})({{n}^{2}}-{{3}^{2}})...({{n}^{2}}-{{r}^{2}}),\] \[n>r,n\in N\] then P is necessarily divisible by

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