If P(n) = 2 + 4 + 6 +?.+ 2n, n Î N, then P(k) = k(k + 1) + 2 Þ P(k + 1) = (k + 1)(k + 2) + 2 for all k Î N. So we can conclude that P(n) = n(n + 1) + 2 for

If P(n) = 2 + 4 + 6 +?.+ 2n, n Î N, then P(k) = k(k + 1) + 2 Þ P(k +

1.	If P(n) = 2 + 4 + 6 +?.+ 2n, n Î N, then P(k) = k(k + 1) + 2 Þ P(k + 1) = (k + 1)(k + 2) + 2 for all k Î N. So we can conclude that P(n) = n(n + 1) + 2 for
A.	All n Î N
B.	n > 1
C.	n > 2
D.	Nothing can be said
Answer» E.

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If P(n) = 2 + 4 + 6 +?.+ 2n, n Î N, then P(k) = k(k + 1) + 2 Þ P(k + 1) = (k + 1)(k + 2) + 2 for all k Î N. So we can conclude that P(n) = n(n + 1) + 2 for

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